Примеры для jQuery .nextAll()

> > > > Примеры

Locate all the divs after the first and give them a class.

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
 
<!doctype html>
<html lang="en">
<head>
  <meta charset="utf-8">
  <title>nextAll demo</title>
  <style>
  div {
    width: 80px;
    height: 80px;
    background: #abc;
    border: 2px solid black;
    margin: 10px;
    float: left;
  }
  div.after {
    border-color: red;
  }
  </style>
  <script src="https://code.jquery.com/jquery-1.10.2.js"></script>
</head>
<body>
 
<div>first</div>
<div>sibling<div>child</div></div>
<div>sibling</div>
<div>sibling</div>
<script>
$( "div:first" ).nextAll().addClass( "after" );
</script>
 
</body>
</html>

Демонстрация:

Locate all the paragraphs after the second child in the body and give them a class.

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
 
<!doctype html>
<html lang="en">
<head>
  <meta charset="utf-8">
  <title>nextAll demo</title>
  <style>
  div, p {
    width: 60px;
    height: 60px;
    background: #abc;
    border: 2px solid black;
    margin: 10px;
    float: left;
  }
  .after {
    border-color: red;
  }
  </style>
  <script src="https://code.jquery.com/jquery-1.10.2.js"></script>
</head>
<body>
 
<p>p</p>
<div>div</div>
<p>p</p>
<p>p</p>
<div>div</div>
<p>p</p>
<div>div</div>
 
<script>
$( ":nth-child(1)" ).nextAll( "p" ).addClass( "after" );
</script>
 
</body>
</html>

Демонстрация: